One Dimensional Motion Physics Practice

Neglecting air resistance.  Any mass would take the same time to hit the ground no matter how massive or minute.  Many times a question may say in a vacuum which means there is no air resistance since air particles are sucked out removed from a vacuum.

Slope of a velocity time graph is acceleration.  Either find the slope or turn it into an equations picking givens off the graph (either way you are doing the same thing)

The rate at which the position or displacement is changing.  This object goes from 16 meters to 8 meters or is going backwards for the 30 seconds. The straight line means the type of motion is constant.

Constant backward velocity

Acceleration which is the rate at which the (Y axis) velocity on a V/T graph is changing.

In the graph provided the object is going 8 meters every seconds (so is moving) but no slope or acceleration.

On a V/T graphs the slope is acceleration.  The slope here is sloped so there is acceleration.  Another way to think about it is by what is happening in the graph.  The object went 0 m/s to 12 m/s during the 30 seconds.  They sped up during the entire time.

On a P/T graphs the slope is velocity.  The slope here is flat so no velocity.  Another way to think about it is by what is happening in the graph.  The object went from 16 meters to 16 meters in 30 seconds.  Therefore is in the same place and did not move.

The ball thrown down will always be traveling faster as they both change by 9.8 m/s² down

Since traveling faster the ball thrown downwards will always be getting further ahead

An acceleration of 9.8 m/s² down means a rock thrown

• 5 m/s down will be going 14.8 m/s a second later (going 14.8 meters in a second - if that rate was maintained)
• 10 m/s down will be going 19.8 m/s a second later (going 19.8 meters in a second - if that rate was maintained)

The one going faster will always be faster and getting further away

The acceleration is always 9.8 m/s² down or averaged to 10 m/s² down.

The ball dropped would have a head start and always be traveling faster downwards

The Y velocity continues to change but is 0 m/s at the top of the flight for an instant.

The acceleration is always 9.8 m/s² down or averaged to 10 m/s² down

The Y velocity continues to change but is 0 m/s at the top of the flight for an instant.

The acceleration is always 9.8 m/s² down or averaged to 10 m/s² down

The Y velocity continues to change but is 0 m/s at the top of the flight for an instant.

The acceleration is always 9.8 m/s² down or averaged to 10 m/s² down anywhere in flight but the velocity does change in the Y axis and is 0 m/s at the top

variable: unit (unit variable)

x : meters (m)

v, v_i, v_f : meters/second (m/s)

a: meters/second² (m/s²)

t: (s)

v = (Δx)/t

The change in displacement over time is the definition of velocity.  See the equation above

north is the direction the 15 m is pointing

The unit defines what the 15 is.  15 what?

meters

• What is your velocity after going 10 meters east followed by 20 meters west in 10 seconds?
• Velocity is a vector so direction matters so displacement divided by time.  Make the directions into signs.
• 10 m east is  +10
• 20 m west is -20
• now calculate displacement and divide that by time ((+10)+(-20))/10
• -10/10 = -1 m/s
• turn the negative back into a direction 1 m/s west

15 m is a magnitude and east is a direction.  This is the vector displacement having both magnitude and direction from the origin to the end.

Distance is a scalar that has no direction. You do nothing with the direction and just add all the individual magnitudes up (10 + 3) here.

You can't put a direction on the final answer since it is a measure of how far you went totally and not a direction.

You should not put a direction on the final answer either since this is not a measure of where you are located but just how far you went in any direction.