Force Physics Practice

Get the force physics practice you need to get an A. Generate a 10 or 20 question quiz from this unit and find other useful practice.

This is an extensive unit. For more specific force practice, follow this link to a list of unit sections. Each section will have a physics practice quiz at the bottom of the page.

Use our equation sheet for guidance on the force equations. This unit uses one dimensional section, force section, and trigonometry reminders section of the equation sheet.

Physics Equation Sheet

Random 10 Questions from the Force Test Bank

10 - Forces Questions

1 / 10

How much force is in a spring that has a spring constant of 4400 N/m that is displaced 0.03 m?

102 N

65 N

321 N

132 N

2 / 10

What happens to the magnitude of force required to stretch a spring 0.1 m when the spring constant increases?

force must increase

force must decrease

force stays the same

3 / 10

What is the tension in a rope when you apply a force of 100 N to pull an object forward in constant motion.

0 N

100 N backward

10 N backward

100 N forward

10 N forward

4 / 10

What is the acceleration of a 1400 N skydiver at terminal velocity?

0 m/s/s

9.8 m/s/s down

9.8 m/s/s up

No net force and no acceleration at terminal velocity

5 / 10

What is the acceleration of a 1400 N skydiver when she encounters 600 N of air resistance? (use g = 9.8 m/s/s)

9.8 m/s/s

0 m/s/s

4.5 m/s/s

5.6 m/s/s

Find Net Force

1400 N weight, which is a vector, directed down and mathematically -1400
600 N air resistance is opposite of motion so up and mathematically is +600
add the vectors together with their signs to get net force
-1400 + 600 = - 800 N or 800 N down

Find Mass

F_w = mg
m =F_w/g
m = 1400/9.8 = 143 kg

Calculate acceleration

F_net= ma

a = F_net/m

a = 800/143 = 5.6 m/s²

6 / 10

What is the mass of an object that accelerates at 4 m/s when 20 N of net force is applied?

5 kg

80 kg

0.2 kg

2.0 kg

7 / 10

What is the net force in the picture above

7 N right

22 N right

8 N left

52 N left

30 left is -30
15 right is +15
7 right is +7

Add them together and turn the sign back into a direction (-30 + 15 + 7 = -8)

8 Newtons Left

8 / 10

What is the net force on a 5 kg object that has a force of 20 N applied to the right and 5 newtons applied to the left?

25 N right

15 N left

25 N left

15 N right

9 / 10

What is the acceleration of a moving object on a 4.0 kg object on a 25° Incline Plane that has a coefficient of friction with the object of 0.43?

0.325 m/s/s

0.56 m/s/s

4.15 m/s/s

11.5 m/s/s

First find the weight (F_w = mg)
Use the weight to find the parallel force down the hill
Use the weight to find the perpendicular force into the hill (also equal to the magnitude of normal force which will be used in the friction equation)
Use the normal force from the step above to figure out the force of friction (F_f = µF_n)
Find the net force (by finding the sum of the forces) subtracting friction uphill from the parallel force downhill
Use the net force in the equation (F_net=ma) to determine the acceleration

10 / 10

Which letter above represents friction?

Your score is

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Random 20 Questions from the Force Test Bank

20 - Forces Questions

1 / 20

Solve for the tension in one of the ropes suspending the object above.

5.4 N

7.35 N

8.5 N

10.3 N

2 / 20

What is the tension in each of two ropes vertically suspending a 45 kg object? (use g = 9.8 m/s/s)

45 kg

441 N

0.218 N

221 N

Tension if a single rope would have the equal magnitude to the weight down. With two ropes both directed up, they are sharing the weight so divide by two.

F_w = mg

F_w = (45)(9.8) = 441 N

441/2 = 220.5 N

3 / 20

What is the tension in a rope when you apply a force of 100 N to pull an object forward in constant motion.

0 N

100 N backward

10 N backward

100 N forward

10 N forward

4 / 20

What is the weight of a 1400 N skydiver at terminal velocity?

0 N

1400 N up

1400 N down

The way the question was stated it was giving you weight which is a force (F_w = 1400 N)

5 / 20

What is the mass of a 1400 N skydiver when she encounters 600 N of air resistance? (use g = 9.8 m/s/s)

13720 kg

143 kg

61.2 kg

81.6 kg

Find Mass

F_w = mg
m =F_w/g
m = 1400/9.8 = 143 kg

6 / 20

What is the acceleration of a 1400 N skydiver that has no air resistance?

0 m/s/s down

9.8 m/s/s down

5 m/s/s down

6.4 m/s/s down

When air resistance on earth is ignored and an object is not too high up, the acceleration due to gravity is 9.8 m/s/s

7 / 20

Acceleration and mass are ______________ related

directly

inversely

8 / 20

What is the mass of an object that accelerates at 4 m/s when 20 N of net force is applied?

5 kg

80 kg

0.2 kg

2.0 kg

9 / 20

What is the net force in the picture above

7 N right

22 N right

8 N left

52 N left

30 left is -30
15 right is +15
7 right is +7

Add them together and turn the sign back into a direction (-30 + 15 + 7 = -8)

8 Newtons Left

10 / 20

What is the net force on a 5 kg object that has a force of 20 N applied to the right and 5 newtons applied to the left?

25 N right

15 N left

25 N left

15 N right

11 / 20

Which statement is related to an objects inertia?

A cup sitting on a car slides off when you hit the breaks

A cup sitting on a windshield slides off because the surface is angled

A cup sitting on a car moves when you grab it

A cup is moving with the car and when you hit the breaks its inertia wants it to keep on going forward. Therefore the cup slides off because it wants to keep its state of motion.

12 / 20

Which has more inertia?

0.34 kg ball

40 kg calf

80 kg boy

Mass is directly related to inertia. The more the mass the more the inertia

13 / 20

What is the minimum force required to start a 0.5 kg brick moving on a wood surface?

0 N

0.45 N

2.2 N

2.9 N

10.9 N

Force applied equals the magnitude of force of friction in constant motion. If you find the force of friction (F_f), you know the Force applied (F_A)

14 / 20

What is the force required to keep a 0.5 kg brick in constant motion on a wood surface?

0 N

0.45 N

2.2 N

2.9 N

10.9 N

15 / 20

What type of friction do you have while an object is at rest?

Static

Kinetic

Rolling

Static Friction: at rest

Kinetic Friction: moving and can be sliding or rolling which would have a lower coefficient of friction than sliding.

16 / 20

What is the acceleration of a moving object on a 4.0 kg object on a 25° Incline Plane that has a coefficient of friction with the object of 0.43?

0.325 m/s/s

0.56 m/s/s

4.15 m/s/s

11.5 m/s/s

First find the weight (F_w = mg)
Use the weight to find the parallel force down the hill
Use the weight to find the perpendicular force into the hill (also equal to the magnitude of normal force which will be used in the friction equation)
Use the normal force from the step above to figure out the force of friction (F_f = µF_n)
Find the net force (by finding the sum of the forces) subtracting friction uphill from the parallel force downhill
Use the net force in the equation (F_net=ma) to determine the acceleration

17 / 20

What happens to the frictional force as the angle of incline increases?

Increases

Decreases

18 / 20

What happens to the normal force as the angle of incline increases?

Increases

Decreases

Larger incline means less force into the hill (equal to the magnitude of normal force) as more of the weight is going into the component downhill instead

19 / 20

Which letter above represents friction?

20 / 20

Which letter above represents weight?

Your score is

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Resources

StickMan Physics Home Page
Force Content Page
Stickman Physics Table of Contents: Use the search bar or click here to easily find a unit or topic
Physics Equation Sheet: commonly used equations, variables, and units
Rule of Ones: analyzing equations to determine how other variables change
Holdensclass.com: Video walk-through of Many Physics Concepts