Force Physics Practice

Get the force physics practice you need to get an A. Generate a 10 or 20 question quiz from this unit and find other useful practice.

This is an extensive unit. For more specific force practice, follow this link to a list of unit sections. Each section will have a physics practice quiz at the bottom of the page.

Use our equation sheet for guidance on the force equations. This unit uses one dimensional section, force section, and trigonometry reminders section of the equation sheet.

Physics Equation Sheet

Random 10 Questions from the Force Test Bank

10 - Forces Questions

1 / 10

Solve for the tension in one of the ropes suspending the object above.

5.4 N

7.35 N

8.5 N

10.3 N

2 / 10

What is the acceleration of a 1400 N skydiver at terminal velocity?

0 m/s/s

9.8 m/s/s down

9.8 m/s/s up

No net force and no acceleration at terminal velocity

3 / 10

What is net force of a 1400 N skydiver at terminal velocity?

0 N

1400 N up

1400 N down

At terminal velocity a person is no longer accelerating so net force is zero because air resistance force is equal to the weight force

4 / 10

What is the acceleration of a 1400 N skydiver that has no air resistance?

0 m/s/s down

9.8 m/s/s down

5 m/s/s down

6.4 m/s/s down

When air resistance on earth is ignored and an object is not too high up, the acceleration due to gravity is 9.8 m/s/s

5 / 10

What is the net force in the picture above

7 N right

22 N right

8 N left

52 N left

30 left is -30
15 right is +15
7 right is +7

Add them together and turn the sign back into a direction (-30 + 15 + 7 = -8)

8 Newtons Left

6 / 10

Joe has a mass of 54 kg. What is his mass on the moon where the acceleration due to gravity is 1.62 m/s²?

539 kg

87.5 kg

54 kg

5.51 kg

Mass does not change. Weight does depending on the acceleration due to gravity.

7 / 10

What is the acceleration of a moving object on a 4.0 kg object on a 25° Incline Plane that has a coefficient of friction with the object of 0.43?

0.325 m/s/s

0.56 m/s/s

4.15 m/s/s

11.5 m/s/s

First find the weight (F_w = mg)
Use the weight to find the parallel force down the hill
Use the weight to find the perpendicular force into the hill (also equal to the magnitude of normal force which will be used in the friction equation)
Use the normal force from the step above to figure out the force of friction (F_f = µF_n)
Find the net force (by finding the sum of the forces) subtracting friction uphill from the parallel force downhill
Use the net force in the equation (F_net=ma) to determine the acceleration

8 / 10

What is the weight of a 4.0 kg object on a 25° frictionless Incline Plane? (Use g = 9.8 m/s²)

0.41 N

4.0 N

9.8 N

39.2 N

9 / 10

Which letter above represents normal force?

10 / 10

Which letter above represents the parallel force?

Your score is

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Random 20 Questions from the Force Test Bank

20 - Forces Questions

1 / 20

What is the displacement of a spring that has a spring constant of 2000 N/m when a force of 500N is applied?

0.25 m

1000000 m

2.5 m

4 m

2 / 20

How much tension must be in a rope attached above an object if the normal force on a 500 N object is 100 N.

300 N up

200 N up

400 N up

600 N up

3 / 20

Solve for the tension in one of the ropes suspending the object above.

5.4 N

7.35 N

8.5 N

10.3 N

4 / 20

What is the tension in each of two ropes vertically suspending a 45 kg object? (use g = 9.8 m/s/s)

45 kg

441 N

0.218 N

221 N

Tension if a single rope would have the equal magnitude to the weight down. With two ropes both directed up, they are sharing the weight so divide by two.

F_w = mg

F_w = (45)(9.8) = 441 N

441/2 = 220.5 N

5 / 20

What is the tension in a rope suspending a 45 kg object? (use g = 9.8 m/s/s)

45 kg

441 N

0.218 N

221 N

Tension up would have the equal magnitude to the weight down

F_w = mg

F_w = (45)(9.8) = 441 N

6 / 20

What is the tension in a rope when you apply a force of 100 N to pull an object forward in constant motion.

0 N

100 N backward

10 N backward

100 N forward

10 N forward

7 / 20

What is the mass of a 1400 N skydiver when she encounters 600 N of air resistance? (use g = 9.8 m/s/s)

13720 kg

143 kg

61.2 kg

81.6 kg

Find Mass

F_w = mg
m =F_w/g
m = 1400/9.8 = 143 kg

8 / 20

Net force causes _____________________. Pick the best answer

motion in the same direction

acceleration in the same direction

motion in the opposite direction

acceleration in the opposite direction

Net force causes an object to accelerate... not just move. Acceleration always occurs in the same direction as net force. If you are pushing something to the right with a greater force than friction, and its net force is to the right, it will accelerate to the right.

9 / 20

What would happen to your weight if you were on a planet with twice the acceleration due to gravity?

It would half

It would double

It would stay the same

It would quadruple

10 / 20

Which changes depending on your location?

mass

weight

Mass (kg) never changes because it is a measure of the matter that you are composed of. You are the same matter on earth or on the moon.

Weight (F_w) changes when g changes. g changes depending on your altitude on earth, in space, or on another planet (it is not always 9.8 m/s²which is why many classes use a more rounded 10 m/s²instead.

(F_w = mg)

11 / 20

Joe has a mass of 54 kg. What is his weight on the earth?

529 N

87.5 N

54 N

5.51 N

F_w = mg

m = 54 kg

g = 9.8 m/s²

F_w = (54)(9.8) = 529.2 N

12 / 20

How much force is required to keep an object in motion?

0 N

It's Weight

Depends on its mass

Newtons first law states an object in motion will stay in motion and an object at rest will stay at rest. No force is needed. Think of an asteroid in space

13 / 20

What is the magnitude of frictional force when 162 N of force is required to keep an object in constant motion?

0 n

10 N

16.2 N

162 N

What is the magnitude of frictional force when 162 N of force is required to keep an object in constant motion?

If there is constant motion there is no acceleration and the net force is zero. The frictional force must equal the force applied in the opposite direction so 162 N as well

14 / 20

What is the downhill force on a 4.0 kg object on a 25° Incline Plane?

0.41 N

4.0 N

16.6 N

35.5 N

15 / 20

What is the acceleration of a moving object on a 4.0 kg object on a 25° Incline Plane that has a coefficient of friction with the object of 0.43?

0.325 m/s/s

0.56 m/s/s

4.15 m/s/s

11.5 m/s/s

First find the weight (F_w = mg)
Use the weight to find the parallel force down the hill
Use the weight to find the perpendicular force into the hill (also equal to the magnitude of normal force which will be used in the friction equation)
Use the normal force from the step above to figure out the force of friction (F_f = µF_n)
Find the net force (by finding the sum of the forces) subtracting friction uphill from the parallel force downhill
Use the net force in the equation (F_net=ma) to determine the acceleration

16 / 20

What happens to the normal force as the angle of incline increases?

Increases

Decreases

Larger incline means less force into the hill (equal to the magnitude of normal force) as more of the weight is going into the component downhill instead

17 / 20

Which number above is where the incline angle would be placed?

18 / 20

Which letter above represents normal force?

19 / 20

Which letter above represents the parallel force?

20 / 20

Which letter above represents weight?

Your score is

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Resources

StickMan Physics Home Page
Force Content Page
Stickman Physics Table of Contents: Use the search bar or click here to easily find a unit or topic
Physics Equation Sheet: commonly used equations, variables, and units
Rule of Ones: analyzing equations to determine how other variables change
Holdensclass.com: Video walk-through of Many Physics Concepts